1)2Ag+ + S2O32- == Ag2S2O3
(2)Ag2S2O3 +H2O == Ag2S + H2SO4
(3)Ag2S2O3 + 3S2O32- == 2[Ag(S2O3)2]3- 、过氧化氢过量时
Na2S2O3 + 4H202 + 2HCl = 2H2SO4+2NaCl+H2O
2、硫代硫酸钠过量时,发生上述反应后,剩余的 硫代硫酸钠会与盐酸继续反应:Na2S2O3 + 2HCl =2NaCl+SO2+S+H2O2Na2S2O3+I2====Na2S4O6+2NaI Na2S2O3+H2SO4=Na2SO4+S↓+SO2↑+H20S2O3^2- + 2H+=SO4^2-+S↓+SO2↑+H2O